Rank the following five capacitors from greatest to smallest capacitance: (1) a 20-mF capacitor with a 4-V potential difference between its plates (2) a 30-mF capacitor with charges of magnitude 90 mC on each plate (3) a capacitor with charges of magnitude 80 mC on its plates, differing by 2 V in potential, (4) a 10-mF capacitor storing energy 125 mJ (5) a capacitor storing energy 250 mJ with a 10-V potential difference
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The five capacitors from greatest to smallest capacitance are:
(3) a capacitor with charges of magnitude 80 mC on its plates, differing by 2 V in potential.
(2) a 30-mF capacitor with charges of magnitude 90 mC on each plate.
(1) a 20-mF capacitor with a 4-V potential difference between its plates.
(4) a 10-mF capacitor storing energy 125 mJ.
(5) a capacitor storing energy 250 mJ with a 10-V potential difference.
Explanation:
Let each of the given capacitors be
Given that,
1). = 20-mF
2). = 30-mF
3). Q = 80 mc, V = 10V
Q =
= Q/V = 80mc/2 = 40 mF
4). = 10-mF
5). E = 250 mV, V = 10-mF
E = 1/2V^2
= 2E/V^2 = (2 * 250)/10^2 = 500/100
= 5mF
Thus,
The correct order of greatest to smallest capacitance is
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