Question

Raoult's law as a special case of Henry law.Explain?​

Answer 1

Answer:

Raoult's Law: The partial pressure of a component in a solution is equal to its mole fraction multiplied by the vapor pressure of that component in pure state. Henry's law: The partial pressure of the volatile component or gas is directly proportional to their mole fraction. Only proportionality constant are different.

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Answer 2

Answer:

At a given temperature liquids vaporize. At equilibrium the pressure exertedby the vapour of the liquid over the liquidphase is referred to as vapour pressure.

According to Raoult’s law, vapour pressure of a volatile component in a given solution ca be defined by pi = pi 0 xi

In an answer of a gas in a fluid one of the segments is volatile to the point that it exists as a gas and solvency is given by Henry's law which expresses that p = KH x