Question

raoults law for two non volatile components

Answer 1

Raoult's law for two non volatile components -

The vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature multiplied by its mole fraction.

Equation -
$p \: = x \: solv \: \times \: P° \: solv$
In this equation, P° is the vapour pressure of the pure solvent at a particular temperature.

xsolv is the mole fraction of the solvent. That is exactly what it says it is - the fraction of the total number of moles present which is solvent.

x solv = (moles of solute)/(total no. of moles)

Answer 2

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