Math, asked by jaswinder7518, 11 months ago

rasheed got a playing top as his birthday present , which surprisingly had no colour on it. he wanted to colour it with his crayons.The top is shaped like a cone surmounted by a hemisphere . The entire top is 5cm in height and the diameter of the top is 3.5 cm . fin the area he has to colour . pie equals 22/7

Answers

Answered by ravi8084132
1

Answer:

r =d/2

3.5/2=1.25

area =22/7×1.25×1.25×5=224. 55

Answered by VelvetBlush
22

Radius of hemisphere = Radius of cone

= \sf{r=\frac{3.5}{2}cm=\frac{7}{4}cm}

Height of cone, \sf{h=5-r=(5-\frac{7}{4})cm=\frac{13}{4}cm}

Slant height of cone,

= \sf\red{l =  \sqrt{ {r}^{2}  +  {h}^{2} }}

=  \sf\red{\sqrt{ {( \frac{7}{4} )}^{2} + {( \frac{13}{4} )}^{2}   } cm}

= \sf\red{ \frac{ \sqrt{49 + 169} }{4} cm}

=  \sf\red{\frac{ \sqrt{218} }{4} cm}

= \sf\red{ \frac{14.765}{4} cm}

= \sf\red{3.691cm = 3.7cm(approx.)}

TSA of the top to be coloured

= CSA of hemisphere + CSA of cone

= \sf\red{2\pi {r}^{2}  + \pi \: rl = \pi \: r(2r + l)}

= \sf\red{ \frac{22}{7}  \times  \frac{7}{4}(2 \times  \frac{7}{4}   + 3.7) {cm}^{2}}

= \sf\red{ \frac{11}{2} (3.5 + 3.7) {cm}^{2}}

= \sf\red{ \frac{11}{2}  \times 7.2 {cm}^{2}}

= \sf\red{11 \times 3.6 {cm}^{2}}

= \sf\red{39.6 {cm}^{2}}

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