Math, asked by Naksharaj, 8 months ago

Rashmi is twice old as Abhay. five years ago her age was three times Abhay age. find the present age​

Answers

Answered by TheMoonlìghtPhoenix
8

Answer:

Step-by-step explanation:

ANSWER:-

\sf{given \ that :-} \\ \sf{Rashmi \ twice \ old \ as \ Abhay }

For Present Ages:-

\bf{ Let  \ the \ age \ of \ Abhay \ be \ x.}

\sf{ So, \  age  \ of \ Rashmi \ will \ be \ 2x}.

Before 5 years:-

  • The age of Rashmi will be 2x-5
  • The age of Abhay will be x-5

A.T.Q,

The age of Rashmi = 3 times the age of Abhay

\sf{2x-5 \ = 3(x -5 )}

\sf{2x-5 = 3x - 15}

\sf{2x-3x = -15+5}

\sf{-x = -10}

\boxed{\bf{x = 10}}

Age of Abhay is 10 years.

Age Rashmi

\implies \sf{x = 10}

\implies \boxed{\sf{2x = 20}}

So , age of Rashmi is 20 years.

Things to Note:-

  • The consideration in the given question is taken as opposite
  • Here, Rashmi was referred as 3 times
  • But I took it to Abhay, and that is the basic to question.
  • Always remember to calculate the second value at last
  • Also , take an constant as x.
  • Do not take different variables.
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