Question

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Answer 1

We know that according to Ohm’s law

V = IR

where

V= potential difference

I= Current

R = Resistance

We can also modify the equation as

I=V/R ——- (i)

Now given that the potential difference across the two ends of the component decreases to half

∴ So let the new potential difference be Vʹ=V/2

Resistance remains constant across the electrical component

So the new current is drawn through the electrical component is Iʹ = Vʹ/R

= (V/2)/R {Substituting Vʹ=V/2 in the above equation}

= (1/2) (V/R)

= (1/2) I = I/2

Therefore, the amount of current flowing through the electrical component is reduced by half.

Answer 2

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