rate constant for 1st order reaction is 60s^-1. how much time will it take to reduce the concentration of the reactant to 1/20th of its initial value
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Explanation:
Given that the rate constant for a first order reaction is 60 s
−1
.
Let a M be the initial concentration.
Final concentration will be
16
a
M.
Rate constant, k=60/s
t=
k
2.303
log(
[A]
[A]
0
)
t=
60
2.303
log
⎝
⎜
⎛
16
a
a
⎠
⎟
⎞
t=4.6×10
−2
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