Question

Rate constant k for 1st order reaction is found to be 2.54 *10^-3 . Calculate 3/4 life

Answer 1

this is your answer
I hope it helps you

Answer 2

The $t_{\frac{3}{4}}$ life is 546.

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  = a

x = amount decayed = $\frac{3a}{4}$

a - x = amount left after decay process =$a-\frac{3a}{4}=\frac{a}{4}$

$t_{\frac{3}{4}}=\frac{2.303}{k}\log\frac{a}{\frac{a}{4}}$

$t_{\frac{3}{4}}=\frac{2.303}{2.54\times 10^{-3}}\log\frac{a}{\frac{a}{4}}$

$t_{\frac{3}{4}}=\frac{2.303}{2.54\times 10^{-3}}\log{4}$

$t_{\frac{3}{4}}=546$

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