Rate law for the reaction A+ 2B → C is found to be
Rate = K[A][B]
Concentration of reactant `B′ is doubled, keeping the concentration of `B′
constant, the value of rate constant will be __________.
(a) the same (b) doubled
(c) quadrupled (d) halved
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Answer:
doubled
Explanation:
because they tols that rate is k(a)(b). so when b is constant a is doubled rate will be doubled
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