Question

Rate law for the reaction A + 2B ⎯→ C is found to be
Rate = k [A][B]
Concentration of reactant ‘B’ is doubled, keeping the concentration of ‘A’
constant, the value of rate constant will be______.
(i) the same
(ii) doubled
(iii) quadrupled
(iv) halved


NCERT Class XII
Chemistry - Exemplar Problems

Chapter 4. Chemical Kinetics

Answer 1

As per the given condition, the value of rate constant will be (i) Same.

Explanation:

• The constant of proportionality in the rate law equation is called a reaction rate constant.
• Its units depend upon the order of reaction and are not dependent on the concentration of the reactions.
• It means that any changes in reactants will not have any effect on the rate constant.
• In the given case, the concentration of the reactant 'B' is doubles whereas the concentration of reactant 'A' is the same.
• As the rate constant is independent of the concentration of reactants, its value in the given case will remain the same.
• Thus option (i) is considered to be the correct answer for the given condition.

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Answer 2

Doubled, becouse k=[B]/[A] ,concentration of B is doubled and concentration of A is remain same..

K =[2B]/[A] = 2K