rate of diffusion of gas is 0.4times that of methane. Calculate weight of gas diffused through a hole in 10 sec. if 32 gm of O2 diffuses through same whole in 4 src.
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rate of diffusion is inversely proportional to the square root of M ( molar mass ) and density.
r1/r2 = root of m2 /m1
r1 be the rate of the gas and r2 be the rate of methane
r1=0.4r2
0.4r2/r2= root of (m2 / 16)
4/10= root of m2 /16
m2 = 256/100
= 2.56 gm
r is directly proportional to V/t
r gas is directly proportional to 1/t
r is directly proportional to root of M
Implies root of M is directly proportional to t
weight of gas diffused = t²
= 100gm
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