Chemistry, asked by muskan371, 1 year ago

rate of diffusion of gases A and B of molecular weights 100 and 81 respectively are in the ratio of

Answers

Answered by AJAYMAHICH
22
According to Graham's law :

the rate of diffusion is inversely proportional to the square root of molar mass.


r1/r2 = √(M2 / M1 )

= √ 81/100
= 9/10



So, the answer is 9:10.
Answered by tripathiakshita48
0

The ratio of the rates of diffusion of gases A and B can be calculated as the square root of the ratio of their molecular weights:

(Diffusion rate of A) / (Diffusion rate of B) = √(Molecular weight of A) /                                                                                                                                             √(Molecular weight of B)

(Diffusion rate of A) / (Diffusion rate of B) = √(100) / √(81)

(Diffusion rate of A) / (Diffusion rate of B) = 10 / 9

So, the ratio of the rates of diffusion of gases A and B is 10:9. This means that gas A will diffuse 10 units in the same amount of time it takes gas B to diffuse 9 units, given equal conditions.

The rate of diffusion of gases is directly proportional to the square root of their molecular weight. It is important to note that the ratio of the rates of diffusion is only dependent on the molecular weights of the gases and not on their temperature, pressure, or volume. This relationship can be used to determine the relative diffusion rates of different gases and has applications in a variety of fields, including air purification and gas chromatography.

For more such questions on the rate of diffusion: https://brainly.in/question/21656030

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