Question

Rate of flow of a liquid flowing through a pipe of radius r smaller and pressure gradient p/l is given by poiseuliles equation v=Tpr

Answer 1

Volume per sec = L^3 T^-1
Now according to above equation
V= P r^4 / ( neta ) l

=( M L^-1 T^-2 ) ( L^4 )
-------------------------------
( M L^-1 T^-1 ) ( L )

= L^3 T^-1

Hence proved !!!

@skb