Question

Rate of formation of SO3 in the reaction 2SO2 + O2→ 2 SO3 is 100 kg min-1

. Hence rate

of disappearance of SO2 will be: it​

Answer 1

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Answer 2

80kg/min

Explanation:

Reaction: $\bf{2}$SO$\small{2}$ + O$\small{2}$ —> $\bf{2}$SO$\small{3}$

By differential rate law:

Rate= R.O.D of SO$\small{2}$ = R.O.A of SO$\small{3}$

$\dfrac{-1}{2}$ $\dfrac{[SO \small{2}]}{dt}$ = $\dfrac{+1}{2}$ $\dfrac{[SO \small{3}]}{dt}$

But quantity is expressed in terms of moles

Rate of formation of SO$\small{3}$ = 100Kg min-¹

$\dfrac{x}{2(16)+4(8)}$ = $\dfrac{100}{2(16)+6(8)}$

$\dfrac{x}{64}$ = $\dfrac{100}{80}$

$\bf{x}$ = 80kg/min

$\sf\boxed{Hence\: Rate\:of\: Disappearance=80kg/min}$

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