Question

Rate of gaseous reaction is halford when volume of vessel vessel is doubled predict order of reaction

Answer 1

Suppose, order of reaction is n and the reaction is A (g) =>Products

Rate = k[A]n ...(i)

When volume is doubled, molar conc. becomes half and rate of reaction gets halved.

Dividing equation (i) by equation (ii),

(2)1 = (2)n

Or n = 1

Answer 2

Hey !!

Suppose the reaction is

                        A -----------> Products, and order of reaction is n. Then,

                           Rate = k [A]^n (or) r = k a^n -------------> (1)

When, volume of vessel is doubled, molar concentration is halved. As rate becomes half, therefore

                           $\frac{r}{2} = k (\frac{a}{2})^{2}$  ---------> (2)

Dividing (1) by (2), we get

                        2 = 2ⁿ (or) n = 1

GOOD LUCK !!