Question

* Ratha made a picture of an eroplane with coloured paper as shown in 12.15
the total area of the paper used​

Answer 1

Answer:

Area of region I:

⇒ 2S=5+5+1=11cm (Isosceles triangle)

S=5.5 cm

Area of I=

s(s−a)(s−b)(s−c)

=

5.5(5.5−5)(5.5−5)(5.5−1)

=.75

11

=2.48 cm

2

Area II: or Area of rectangle =l×b

=6.5×1

=6.5 cm

2

Area III: Its a trapezium

So, we need to calculate the perpendicular height

=(1)

2

−(0.5)

2

=

0.75

=0.86 cm

Area of trapezium

= Area of parallelogram + Area of equilateral triangle

=0.866×1+

4

3

(1)

2

=0.86+0.43=1.29 cm

2

Area of region IV= Area of region V=

2

1

×6×1.5

=4.5 cm

2

Total area of paper used =2.48+6.5+1.29+4.5+4.5

=19.27 cm

2

Answer 2

Answer:

4×4 total area of the paper yes means full papet