Math, asked by Nitin00777, 1 year ago

Rathin is now 16 years old... explain ans.. ⭐be star❤️❤️

Attachments:

Answers

Answered by dubey1881
7

Answer:


Step-by-step explanation:

Present age of Rathin = 16 years.


Present age of his Cousin = 7 years.


Let x be the number of years after which Rathin's age will be 1.5 times of his cousin's age.


Therefore 16 + x = 1.5(7+x)


Which implies 16 + x = 10.5 + 1.5x


Which gives x=11 years.


Therefore after 11 years Rathin's age will be 1.5 times his cousin's age.


Nitin00777: ooho
Nitin00777: which class of u
Nitin00777: mechanical engineer
Nitin00777: hhhahha shru status mst.. with lovely dp❤️❤️❤️❤️
Answered by biswajit4074
0

Step-by-step explanation:

Let after N years Rathin's age be 1.5 times it’s cousin.

Rathin is now 16 years old while his cousin is 7 years,

⇒ (16 + N) = 1.5(7 + N)

⇒ 32 + 2N = 21 + 3N

⇒ N = 11

Similar questions