Question

ratilnalise the denomination of 1 byroot 2+root3+root5​

Answer 1

Answer:

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Answer 2

Answer:

$\frac{1.11}{6}$✔✔

Step-by-step explanation:

$\frac{1}{ \sqrt{2} + \sqrt{3} + \sqrt{5} } \times \frac{ \sqrt{2} + \sqrt{3} - \sqrt{5} }{\sqrt{2} + \sqrt{3} - \sqrt{5}} \\ = \frac{ \sqrt{2} + \sqrt{3} - \sqrt{5} }{( { \sqrt{2} + \sqrt{3} })^{2} - { \sqrt{5} }^{2} } \\ = \frac{1.41 + 1.73 - 2.23}{ 2 + 3 + 2 \times \sqrt{6} - 5 } \\ = \frac{3.14 - 2.23}{2 \sqrt{6} } \\ = \frac{0.91}{2 \sqrt{6} } \times \frac{\sqrt{6} }{\sqrt{6} } \\ = \frac{0.91 \sqrt{6} }{12} \\ = \frac{2.22}{12}\\=\frac{1.11}{6}$

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