Question

ratinalise the denominator.​

Answer 1

AnsWer :

2√3 - √6.

QuestioN :

Rationalise the denominator -

$\tt \dagger \: \: \: \: \: \dfrac{3 \sqrt{2} }{ \sqrt{3} + \sqrt{6} }$

SolutioN :

$\tt : \implies \dfrac{3 \sqrt{2} }{ \sqrt{3} + \sqrt{6} }$

$\tt : \implies \dfrac{3 \sqrt{2} }{ \sqrt{3} + \sqrt{6} } \times \dfrac{ \sqrt{3} - \sqrt{6} }{ \sqrt{3} - \sqrt{6} }$

$\tt : \implies \dfrac{3 \sqrt{2} \times ( \sqrt{3} - \sqrt{6} )}{{ \sqrt{3} }^{2} - {\sqrt{6} }^{2} }$

$\tt : \implies \dfrac{3 \sqrt{6} - 6\sqrt{3} }{3 - 6 }$

$\tt : \implies \dfrac{3 \sqrt{6} - 6\sqrt{3} }{ - 3 }$

☛ Taking Common ( 3 )

$\tt : \implies \dfrac{3( \sqrt{6} - 2\sqrt{3}) }{ - 3 }$

$\tt : \implies - ( \sqrt{6} -2\sqrt{3})$

$\tt : \implies 2\sqrt{3}-\sqrt{6}$

✡ Therefore, the required value is 2√3 - √6.

Answer 2

Answer:

Hi mate

Step-by-step explanation:

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