Question

ratinalize the denominator :1/(2√7+3√3)​

Answer 1

Your answer.............

Answer 2

$\frac{1}{2 \sqrt{7} + 3 \sqrt{3} } \times \frac{2 \sqrt{7} - 3 \sqrt{3} }{2 \sqrt{7} - 3 \sqrt{3} } \\ \\ = \frac{2 \sqrt{7} - 3 \sqrt{3} }{ {(2 \sqrt{7)} }^{2} - {(3 \sqrt{3)} }^{2} } \\ \\ = \frac{2 \sqrt{7} - 3 \sqrt{3} }{28 - 27} \\ \\ = \frac{2 \sqrt{7} - 3 \sqrt{3} }{1} \\ \\ = 2 \sqrt{7} - 3 \sqrt{3}$

Hope it helps.