Question

Ratinolise the denominator
$2 + \sqrt{2} \div 2 - \sqrt{3}$
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$= \frac{2 + \sqrt{2} }{2 - \sqrt{3} } \\ \\ = \frac{2 + \sqrt{2} }{2 - \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \\ = \frac{(2 + \sqrt{2})(2 - \sqrt{3} ) }{4 - 3} \\ \\ = 4 - 2 \sqrt{3} + 2 \sqrt{2} - \sqrt{6}$