ratio 2:5. Find the angles of the triangle.
One of the exterior angle of a triangle is 105° and the interior opposite angles are in ratio 2:5 find the angle of the triangle
Answers
✬ Angles = 30° ,75° & 75° ✬
Step-by-step explanation:
Given:
- Measure of exterior angle of triangle is 105°.
- Ratio of opposite angles of triangle is 2 : 5.
To Find:
- Measure of angles of triangle ?
Solution: Let x be the common in given ratios and ABC be a triangle.
Here in triangle ABC we have
- ∠ACD = exterior angle of ∆.
- ∠BAC : ∠CBA = 2 : 5.
[ Remind a theorem ]
- The sum of exterior angle of a triangle is equal to the sum of its opposite interior angles.
- ∠BAC & ∠CBA are opposite interior angles.
∠BAC + ∠CBA = ∠ACD
2x + 5x = 105°
7x = 105°
x = 105°/7
x = 15°
So , measure of
- ∠BAC = 2 × 15 = 30°
- ∠CBA = 5 × 15 = 75°
Now by using a property of triangle.
[ Angle sum property ]
- It states that sum of all interior angles of a ∆ is equal to 180°.
➟ ∠BAC + ∠CBA + ∠ACB = 180°
➟ 30° + 75° + ∠ACB = 180°
➟ ∠ACB = 180° – 105°
➟ ∠ACB = 75°
We have the property that, in a triangle exterior angle is equal to the sum of interior opposite angles.
Given, the interior opposite angles to the exterior angle 105° are in the ration 2:5
...2x + 5x = 1050
7x=105° =
X = 15°
Therefore the interior opposite angles to the angle 105° are 2 x = 2(15) = 30° and 5x = 5(15) = 75° =
Let the third angle of the triangle be C We have the sum of interior angles of a triangle is
180°
.:. 30° + 75° + C = 1800
C = 180° - 75° 30° = 180° - 105°
C = 75°
hence the angles are 30⁰,75⁰,75⁰