Question

RATIO BETWEEN THE LATERAL AREA AND BASE AREA OF A CUBOID WHOSE LENGTH AND BREADTH ARE EQUAL AND HEIGHT IS TWO TIMES OF LENGTH.​

Answer 1

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$l=80cm,b=40cm,h=20cm$

$Therefore,$

$TSA = 2(lb+bh+hl)=2$

$(80×40+40×20+80×20) \\ =11200 cm2$

$LSA = 2(l+b)h=2(80+40)20 \\ =4800 cm {}^{2}$

Answer 2

Step-by-step explanation:

RATIO BETWEEN THE LATERAL AREA AND BASE AREA OF A CUBOID WHOSE LENGTH AND BREADTH ARE EQUAL AND HEIGHT IS TWO TIMES OF LENGTH.