Question

ratio of 2 digit no. to a number obtained by reversing its digits is 4:7.if the sum of its digits is 9 find the number

Answer 1

EXPLANATION.

Let the ten's digit place be = x

Let the unit digit place be = y

original number = 10x + y

reversing number = 10y + x

To find the number.

According to the question,

ratio of two digit number obtained by

reversing it's digit = 4:7

=> 10y + x / 10x + y = 4/7

=> 7 ( 10y + x) = 4 ( 10x + y)

=> 70y + 7x = 40x + 4y

=> 66y = 33x

=> 2y = x ...... (1)

If the sum of its digit is = 9

=> x + y = 9 ...... (2)

from equation (1) and (2) we get,

=> put the value of x = 2y in equation (2)

we get,

=> 2y + y = 9

=> 3y = 9

=> y = 3

put the value of y = 3 in equation (1)

we get,

=> x = 2(3)

=> x = 6

Therefore,

original number = 10x + y

=> 10(6) + 3 = 63

Answer 2

Answer:

⭐ Question ⭐

✏ Ratio of 2 digit no. to a number obtained by reversing its digits is 4:7.if the sum of its digits is 9 find the number.

⭐ To Find ⭐

✏ We have to find the number.

➡Let the ten's digit place be = x

➡Let the unit digit place be = y

➡Original number = 10x + y

➡Reversing number = 10y + x

▶According to the question,

➡Ratio of two digit number obtained by reversing it's digit = 4:7

=> 10y + x/ 10x + y = 4/7

=> 7 ( 10y + x) = 4 ( 10x + y)

=> 70y + 7x = 40x + 4y

=> 66y = 33x

=> 2y = x ......(1)

➡If the sum of its digit is = 9

=> x+y = 9 ....... (2)

➡From equation (1) and (2) we get,

✍ Putting the value of x = 2y in equation (2) we get,

=> 2y +y = 9

=> 3y = 9

=> y = 3

✍ Put the value of y = 3 in equation (1) we get,

=> x = 2(3)

=> x = 6

Therefore, original number = 10x + y

=> 10(6) + 3 = 63

▶ Hence,

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Step-by-step explanation:

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