Math, asked by rohitguddin, 10 months ago

ratio of 2nd term to 6th term is 2 :5 in an ap. 8th term is 26 what is the 10th term​

Answers

Answered by anjaligupta817890
1

Answer:

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Answered by MisterIncredible
5

Given :-

Ratio of 2nd term to the 6th term is 2 : 5 .

8th term is 26 .

Required to find :-

  • 10th term ?

Formula used :-

\dag{\boxed{\tt{  {a}_{nth} = a + ( n - 1 ) d  }}}

Solution :-

Given data :-

Ratio of 2nd term to 6th term is 2 : 5

8th term is 26

we need to find the 10th term

So,

From the given data let's find the values of a ,d

Here,

Ratio of 2nd term to 6th term is 2 : 5

2nd term : 6th term = 2 : 5

But,

2nd term can be represented as ;

a + d

Similarly,

6th term can be replaced as ;

a + 5d

This implies ;

a + d : a + 5d = 2 : 5

This can also be written as ;

 \tt{ \dfrac{a + d}{a + 5d} =  \dfrac{2}{5}}

By, cross multiplication

5 ( a + d ) = 2 ( a + 5d )

5a + 5d = 2a + 10d

5a - 2a + 5d - 10d = 0

3a - 5d = 0 \longrightarrow{\tt{\bf{Equation-1}}}

consider this as equation - 1

However,

It is also mentioned that ;

8th term = 26

So,

8th term is also represented as ; a + 7d

a + 7d = 26 \longrightarrow{\tt{\bf{Equation-2}}}

consider this as Equation 2

Now,

Multiply equation 2 with 3

3 ( a + 7d ) = 3 ( 26 )

3a + 21d = 78 \longrightarrow{\tt{\bf{Equation-3}}}

consider this as equation 3

Subtract equation 1 from Equation 3

 \tt{3a + 21d = 78} \\  \tt{3a - 5d = 0} \\  \underline{( - )( + ) \:  \:  \: ( - ) \:  \:  \:  \: } \\   \underline{\:  \:  \:  \:  \:  \:  \tt + 26d = 78} \\  \\  \implies  \tt 26d = 78 \\  \\  \implies \tt d  =  \dfrac{78}{26} \\  \\  \implies \tt d = 3

substitute the value of d in equation 2

a + 7d = 26

a + 7 ( 3 ) = 26

a + 21 = 26

a = 26 - 21

a = 5

Hence,

  • First term ( a ) = 5

  • Common difference ( d ) = 3

Using the formula ;

\dag{\boxed{\tt{  {a}_{nth} = a + ( n - 1 ) d }}}

\longrightarrow{\tt{ {a}_{nth} = {a}_{10} }}

\longrightarrow{\tt{ {a}_{10} = 5 + ( 10 - 1 ) 3 }}

\longrightarrow{\tt{ {a}_{10} = 5 + ( 9 ) 3 }}

\longrightarrow{\tt{ {a}_{10} = 5 + 27 }}

\longrightarrow{\tt{ {a}_{10} = 32 }}

Therefore,

10th term = 32

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