Question

Ratio of active masses of 22g CO,, 3g H, and 7g
N, in a gaseous mixture :-
(1) 22:3:7
(2) 0.5: 3:7
(3) 1: 3:1
(4) 1: 3: 0.5​

Answer 1

Explanation:

ANSWER

=0.25moles

Total moles = 0.5+1.5+0.25=2.25

Ratio of active masses =0.5/2.25:1.5/2.25:0.25/2.25=1:3:0.5