Question

ratio of AD to DC is 3:2. If the area of triangle ABC is 40cm^2. Find area of triangle BDC

Answer 1

See the answer below

Answer 2

Answer: Hence, Area of ΔBDC = 16 cm².

Step-by-step explanation:

Since we have given that

Ratio of AD to DC = 3 : 2

Area of ΔABC = 40 cm²

We need to find the area of ΔBDC.

As we can see that

DC = $\dfrac{2}{5}AC$

So, it implies that

Area of ΔBDC $\dfrac{2}{5}\times \text{Area of ABC}$

So, Area of ΔBDC = $\dfrac{2}{5}\times 40=2\times 8=16\ cm^2$

Hence, Area of ΔBDC = 16 cm².