Math, asked by soumini8963, 7 months ago

ratio of ages of seeta and geeta is 9:15. five years before their ages were in the ratio of 2:5. What are their present ages? ​

Answers

Answered by Anonymous
2

✪ Question ✪

The ratio of ages of Seeta and Geeta is 9:15. five years before their ages were in the ratio of 2:5. What are their present ages?

✪ Given ✪

The ratio of ages of Seeta and Geeta is 9:15. five years before their ages were in the ratio of 2:5.

✪ To find ✪

Their present ages.

✪ Solution ✪

Let their present ages be 9x and 15x years.

According to condition,

(9x-5)/(15x-5) = 2/5

↝ 5(9x-5) = 2(15x-5)

↝ 45x-25 = 30x-10

↝ 45x-30x = -10+25

↝ 15x = 15

↝ x = 15/15

↝ x = 1

✪ Hence ✪

x = 1

☞ 9x = (9×1) = 9

☞ 15x = (15×1) = 15

✪ Therefore ✪

The present ages of Seeta and Geeta are 9 years and 15 years respectively.

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✪ Verification ✪

(9-5)/(15-5) = 2/5

↝ 4/10 = 2/5

↝ 4/10÷2/2 = 2/5

↝ 2/5 = 2/5

So, L.H.S = R.H.S.

Hence, verified.

๑ Hope this helps you. ๑

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