Ratio of angularbmomentum of 2nd and 1st bohrs orbit of hydrogen atom
Answers
Answered by
0
Heya ✌✌
Here is u r Ans ➡
✨According to Bohr's first postulate for hydrogen atom, the angular momentum of an electron in nth orbit is nh/(2pi). Then, in the second orbit for which n=2, the angular momentum will be 2h/(2pi)=h/pi. Here, h is Planck's constant=6.63x10^-34 J-s.
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Hope This Helps u ☺.
Here is u r Ans ➡
✨According to Bohr's first postulate for hydrogen atom, the angular momentum of an electron in nth orbit is nh/(2pi). Then, in the second orbit for which n=2, the angular momentum will be 2h/(2pi)=h/pi. Here, h is Planck's constant=6.63x10^-34 J-s.
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Hope This Helps u ☺.
Similar questions