Question

ratio of average speed of He and SO2 at 27c will be

Answer 1

average speed =(8.R.T/π.m)^1/2

where R is universal gas constant
T temperature
M molecular mass

Answer 2

Ratio of average speed of He and $SO_2$ at $27^0C$ will be 4.

Explanation:

The formula for average speed is  :

$\nu_{av}=\sqrt{\frac{8RT}{\pi M}}$

where,

R = gas constant  

T = temperature  

M = Molecular Mass

Now putting all the values:

$\frac{\nu_{av_{He}}}{\nu_{av_{SO_2}}}=\frac{\sqrt{\frac{8RT}{\pi M_{He}}}}{\sqrt{\frac{8RT}{\pi M_{SO_2}}}}$

$\frac{\nu_{av_{He}}}{\nu_{av_{SO_2}}}=\frac{\sqrt{M_{SO_2}}}{\sqrt{M_{He}}}$

$\frac{\nu_{av_{He}}}{\nu_{av_{SO_2}}}=\frac{\sqrt{64}}{\sqrt{4}}}$

$\frac{\nu_{av_{He}}}{\nu_{av_{SO_2}}}=\sqrt{16}$

$\frac{\nu_{av_{He}}}{\nu_{av_{SO_2}}}=4$

Thus ratio of average speed of He and $SO_2$ at $27^0C$ will be 4.

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