Question

Ratio of corresponding sides of two similar triangles is 2:5,if the area of the small triangle is 64 sq.cm.then what is the area of the bigger triangle ?

Answer 1

Ratio of Area : Ratio of length:

$\dfrac{\text{Area 1}}{\text{Area 2}} =\bigg( \dfrac{\text{Length 1}}{\text{length 2}} \bigg)^2$

Find the bigger Area:

$\dfrac{\text{64} }{\text{Area 2}}=\bigg( \dfrac{\text{2}}{\text{5}} \bigg)^2$

$\dfrac{\text{64} }{\text{Area 2}} = \dfrac{4}{25}$

$\text {Area 2} = (64 \times 25) \div 4$

$\text {Area 2} = 400 \text { cm}^2$

Answer: The area of the larger triangle is 400 cm²

Answer 2

❤❤Here is your answer ✌ ✌

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Ratio of area:Ratio of length

Area n1/Area n2 = (length n1/length n2)^2

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we will find bigger area :-

64/area n2 = (2/5)^2

64/area n2 =4/25

area n2=[64×25]/4

area n2=400cm^2

Area of bigger triangle is 400cm^2