Question

Ratio of Cp, and Cv of a gas 'X' is 1:4. The
number of atoms of the gas 'X' present in
11.2 L of it at NTP will be [CBSE AIPMT 1989]
(a) 6.02 x 1023
(b) 1.2 x 1023
(c) 3.01 x 1023
(d) 2.01 x 1023​

Answer 1

Answer:

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