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Ratio of de broglie wavelength of electron and proton with same kinteic energy

Answers

Answered by parimalgunjan096
2

Ratio of de Broglie wavelength of electron and proton is square root of mass of proton divided by square root of mass of electron

Answered by muscardinus
2

The ratio of De Broglie wavelength of electron and proton is 0.0233.

Explanation:

The relation between kinetic energy k and momentum p is given by :

k=\dfrac{p^2}{2m}

Since,

\lambda=\dfrac{h}{p}

The wavelength of proton is :

\lambda_p=\dfrac{h}{\sqrt{2m_pE} }...............(1)

The wavelength of electron is :

\lambda_e=\dfrac{h}{\sqrt{2m_eE} }.........(2)

From equation (1) and (2) we get :

\dfrac{\lambda_p}{\lambda_e}=\sqrt{\dfrac{m_e}{m_p}}

\dfrac{\lambda_p}{\lambda_e}=\sqrt{\dfrac{9.1\times 10^{-31}}{1.67\times 10^{-27}}}

\dfrac{\lambda_p}{\lambda_e}=0.0233

So, the ratio of De Broglie wavelength of electron and proton is 0.0233. Hence, this is the required solution.

Learn more,

De Broglie wavelength

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