Question

Ratio of distances covered by object falling freely under gravity in 1st, 2nd and 3rd second is _____ (A)1:3:5 (B)1:2:5 (C)1:4:9 (D)1:5:9​

Answer 1

Answer:

A) 1:3:5

Explanation:

S is directly proportional to 2n-1.

S1:S2:S3 = 2(1) -1:2(2) -1:2(3) -1

= 2-1 : 4-1 : 6-1

= 1:3:5

Answer 2

Answer:$x^{2}$

A is correct option.

Explanation:

we know that  , s = ut + (1/2)a$t^{2}$

considering  t₀ = 0 sec  , t₁ = 1  sec , t₂ = 2 sec, t₃ = 3 sec

And given , u = 0

Now we can write ,

s₁ - s₀ = (1/2)g( t₁² - t₂² ) = g/2

s₂ - s₁ = (1/2) g ( t₂² - t₁² ) = 3g/2

s₃ - s₂ = (1/2) g ( t₃²- t₂² ) = 5g/2

So, the ratio of distances covered in 1st, 2nd and 3rd seconds is 1:3:5 .

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