Question

Ratio of frequencies of two Bohr orbits of hydrogen atom is 1:27. The ratio of their radii is​

Answer 1

Dear Student,

● Answer -

9:1

◆ Explaination -

Frequency of Bohr's orbit is inversely proportional to n³.

f1/f2 = (n2/n1)³

1/27 = (n2/n1)³

1/3 = n2/n1

n1/n2 = 3

Radius of Bohr's orbit is directly proportional to square of Bohr's orbit.

r1/r2 = (n1/n2)²

r1/r2 = 3²

r1/r2 = 9

Therefore, ratio of radii is 9:1.

Thanks for asking...