Question

Ratio of Henry's constant KH pf two inert gases A and B is 2 at a given temperature. A mixture containing 4 moles of gas A and 8 moles of gas B is bubbled through water is allowed to attain equilibrium what will be ratio of mole fractions of gases in the solution??

Answer 1

Given that,

Concentration of gas A = 4 moles

Concentration of gas B = 8 moles

We need to calculate the ratio of fractions of gases in the solution

Using formula of Henry's constant

$H_{AB}=\dfrac{c_{a}}{c_{b}}$

Where, $c_{a}$ = concentration of gas A

$c_{b}$ = concentration of gas B

Put the value into the formula

$H_{AB}=\dfrac{4}{8}$

$H_{AB}=\dfrac{1}{2}$

Hence, The ratio of fractions of gases in the solution is $\dfrac{1}{2}$