Question

ratio of kinetic energy required for the satellite to escape the Earth surface to the kinetic energy required to orbit just close to the earth is:

Answer 1

Answer: 2:1

Explanation:

Escape velocity is given by:

$v = \sqrt{\frac{2GM}{R}}$

orbital velocity:

$v' = \sqrt{\frac{GM}{R}}$

Ratio of velocities:

$\frac{v}{v'} = \frac{\sqrt 2}{1}$

Ratio of kinetic energies:

$\frac{0.5 mv^2}{0.5mv'^2} = \frac{v^2}{v'^2} = \frac{2}{1}$

Answer 2

Answer:hope my answer helps you....

Explanation: