Question

Ratio of length of parallel sides of a trapezium is 2:3. Distance
between them is 16cm. If the area of trapezium is 320cm² Find length of parallel sides.​

Answer 1

Answer:

CONGRATULATIONS

Given

Ratio of length of parallel sides of a trapezium is 2:3. Distance between them is 16cm. If the area of trapezium is 320cm²

To find

Length of parallel sides

Solution

✰ Ratio of length of parallel sides = 2 : 3

✰ Distance between parallel sides = 16 cm

✰ Area of trapezium = 320 cm²

Let the parallel sides be 2x and 3x

$\\{\underline{\boxed{\bf{\red{Area\:of\:trapezium=\dfrac{1}{2}\times{(a+b)}\times{h}}}}}}$

$\implies\sf 320 = \dfrac{1}{2}\times{(2x+3x)}\times{16}$

$\implies\sf 320=\dfrac{1}{2}\times{5x}\times{16}$

$\implies\sf 320=5x\times{8}$

$\implies\sf \dfrac{320}{8}=5x$

$\implies\sf 40=5x$

$\implies\sf x=\cancel\dfrac{40}{5}$

$\implies\sf x=8cm$

$\large\bigstar\: \large{\underline{\sf{\purple{Length\:of\:parallel\:sides}}}}\: {\bigstar}$

Length of the first parallel side = 2x = 16 cm

Length of the second parallel side = 3x = 24cm

______________________________________

Answer 2

Answer:

Given

Ratio of length of parallel sides of a trapezium is 2:3. Distance between them is 16cm. If the area of trapezium is 320cm²

To find

Length of parallel sides

Solution

✰ Ratio of length of parallel sides = 2 : 3

✰ Distance between parallel sides = 16 cm

✰ Area of trapezium = 320 cm²

Let the parallel sides be 2x and 3x

Area of Trapezium = ½ × (a + b) × h

320 = ½ × (2x + 3x) × 16

320 = ½ × (5x) × 16

320 = 5x × 8

320/8 = 5x

40 = 5x

x = 40/5 {Cancel 40; 5 × 8 = 40}

x = 8 cm

${ \mathfrak{ \underline{ \pink{ \: ➪ \: Length \: of \: Parallel \: sides }}}}$

Length of the first parallel side = 2x = 16 cm

Length of the first parallel side = 2x = 16 cmLength of the second parallel side = 3x = 24cm

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