Question

ratio of magnitudes of electric force in air and water between an electron and proton is: a)K b)1/K c)1 d)0

Answer 1

k ,the dielectric constant

Answer 2

Hey buddy,

● Answer -
F/F' = k

● Explaination -
Let k be dielectric constant of water.

Electrostatic force between two charges is given by Coulomb's law -
F = (1/4πε) q1q2/d^2

In air, q1 = +e & q2 = -e, ε = ε0,
F = (1/4πε0) (e/d)^2

In water, q1 = +e & q2 = -e, ε = kε0,
F' = (1/4πkε0) (e/d)^2

Dividing F by F',
F/F' = [(1/4πε0)(e/d)^2] / [(1/4πkε0)(e/d)^2]
F/F' = k

Therefore, ratio of magnitudes of electric force in air and water between an electron and proton is *k*.

Hope this helped you.