Ratio of moles of methanol and acetic acid containing eaual moles of oxygen atoms will be
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Explanation:
Formula of Methanol => CH3OH
Formula of Acetic acid => CH3COOH
If observed carefully the ratio of oxygen from Methanol : Acetic acid => 1:2
this multiplying co-efficient of Methanol by 2
therefore
Ratio of moles of methanol and acetic acid containing equal moles of oxygen atoms will be==> 2:1
since two moles of CH3OH ==> 2CH3OH contains two moles of Oxygen .And one mole of CH3COOH also contains 2 moles of Oxygen.
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