Question

ratio of no. of oxygen atom in 1g O2 & 1g O3 ?

Answer 1

HEY.

HERE IS THE ANSWER.

As 32g of O2 has N° molecules of O2
{here N° is Avogadro's no.}
so, 1g of O2 has N°/32 molecules of O2
so, 1g of O2 has 2N°/32 atoms of O

Similarly, 1g of O3 has 3N°/48 atoms of O

so, required ratio is (2N°/32)/(3N°/48)
=(2/32)/(3/48)
=2×48/3×32 = 1:1

So, the required ratio is 1 : 1.

Thanks.