Ratio of present age of A&B is 4:5,while that of C&D is 6:7 if 10 years ago ratio of age of A&Cis 1:2andthat of B&D is 3:5 find average age of A,B,C,D together
Answers
Answered by
7
Answer:
A=4x
B=5x
C=6x
D=7x
A to Q
4x-10/6x-10=1/2
8x-20=6x-10
2x=-10+20
2x=10
x=5
so now A=4*5=20
B=5*5=25
C=6*5=30
D=7*5=35
Average of a, b, c, d=20+25+30+35/4=27.5
Answered by
1
Answer:
Ages of A,B,C,D are 20,25,30,35 years respectively.
Step-by-step explanation:
Given,Ratio of present age of A and B is 4:5.
and ratio of present age of C and D is 6:7
10 year ago,
Ratio of ages of A and C is 1:2 and ratio of ages of B and D is 3:5.
Let present ages of A,B,C,D are 4x,5x,6x and 7x respectively.
Before 10 years,age of A was (4x-10) years
and age of C was (6x-10) years.
According to question,
By cross multiplication,
So age of A is years.
Age of B is years.
Age of C is years.
Age of D is years.
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