Ratio of present ages of Pankaj and Punit is 5:6 and the sum of their ages is 33 years. What will be difference (in years) of their ages?
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Answer:
Pankaj = 15 yrs
Punit = 18 yrs
Step-by-step explanation:
Let the common multiple be 'x'
Therefore,
5x + 3x = 33
11x =33
x=3
Pankaj's age = 5x = 5*3 = 15
Punit's age = 6*3 = 18
Answered by
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Let the present age of Pankaj and Punit be ‘5x’ and ‘6x’ respectively.
Given, the sum of their ages are 33.
So,
5x + 6x = 33
11x = 33
x = 33/11
x = 3
So their ages are:-
Puneet age = 5x = 5*3 = 15
And Punit age = 6x = 6*3 = 18
So difference between their ages (in year ) = 18-15 = 3
As the difference in the year is same as the difference in age. It is just for confusion.
Given, the sum of their ages are 33.
So,
5x + 6x = 33
11x = 33
x = 33/11
x = 3
So their ages are:-
Puneet age = 5x = 5*3 = 15
And Punit age = 6x = 6*3 = 18
So difference between their ages (in year ) = 18-15 = 3
As the difference in the year is same as the difference in age. It is just for confusion.
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