Math, asked by Lokita1722, 10 months ago

Ratio of present ages of Pankaj and Punit is 5:6 and the sum of their ages is 33 years. What will be difference (in years) of their ages?

Answers

Answered by sahilyadav62442
0

Answer:

Pankaj = 15 yrs

Punit = 18 yrs

Step-by-step explanation:

Let the common multiple be 'x'

Therefore,

5x + 3x = 33

11x =33

x=3

Pankaj's age = 5x = 5*3 = 15

Punit's age = 6*3 = 18

Answered by Devashish15
0
Let the present age of Pankaj and Punit be ‘5x’ and ‘6x’ respectively.

Given, the sum of their ages are 33.

So,
5x + 6x = 33
11x = 33
x = 33/11
x = 3

So their ages are:-
Puneet age = 5x = 5*3 = 15
And Punit age = 6x = 6*3 = 18

So difference between their ages (in year ) = 18-15 = 3


As the difference in the year is same as the difference in age. It is just for confusion.
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