Question

ratio of RMS velocity of CH4 and O2 at 400K and 800K respectively is​

Answer 1

Answer:

please mark me as brailest

Answer 2

The root mean square velocity of the different molecule is the square root of the mean of the squares of the speeds.

Explanation:

The formula for RMS velocity = $\sqrt\frac{3RT}{M}$.

Here,

R=  Universal Gas Constant

T= Temperature in Kalvin

M= Molecular weight of the compound.

The ratio of RMS velocity of methane ($CH_4$) and oxygen($O_2$)

Molecular weight of methane= 16g/mol

Temeprtaure(given) = 400K

RMS=

Molecular weight of oxygen= 16g/mol

Temperature(given) = 800K

Ratio RMS of methane and oxygen=

$\sqrt\frac{\frac{3R400}{16} }{\frac{3R800}{16} } \\\sqrt\frac{400}{800} \\\sqrt \frac{1}{2}$

So, the answer is

$\sqrt\frac{1}{2}$.