Ratio of sum of mth and the sum of nth is in the ratio m^2:n^2, then ratio btw mth:nth term
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Sn/Sm = m²/n²
=m/2{ 2.1 + (m -1)2 }/n/2{ 2.1+( n -1)2}
here we convert just like standard form of Sm and Sn
now,
for Sn and Sm
a = 1 and d = 2 { a = 1st term and d = common difference }
Now,
Tm/Tn = { a + ( m -1)d}/{ a + (n -1)d }
= { 1 + 2m -2)}/{ 1 + (n -1)2}
= (2m -1)/(2n -1)
=m/2{ 2.1 + (m -1)2 }/n/2{ 2.1+( n -1)2}
here we convert just like standard form of Sm and Sn
now,
for Sn and Sm
a = 1 and d = 2 { a = 1st term and d = common difference }
Now,
Tm/Tn = { a + ( m -1)d}/{ a + (n -1)d }
= { 1 + 2m -2)}/{ 1 + (n -1)2}
= (2m -1)/(2n -1)
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