Question

Ratio of tge age of a man and his wife is 6:5 .After 16 years, the ratio 10:9.Find tge husband's age when the wife was born.

Answer 1

let the husband age be 6x

let wife age be 5x

after 16 years

their ages are

husband =10x

wife=9x

ATQ

5x+16+6x+16=10x+9x

11x+32=19x

11x-19x=-32

-8x=-32.

x=-32/-8

x=4

so, husband present age =6x=6*4=24

wife present age=5x=5*4=20

so wife was born 20years ago

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hello Friend}}}$

Here is your answer

Let the age of a man 6x
and his wife age is 5x

AFTER 16Years
Man age is 6x + 16
Wife age is 5x + 16

Now ATQ
$\frac{6x + 16}{5x + 16} = \frac{10}{9} \\ 9(6x + 16) = 10(5x + 16) \\ 54x + 144 = 50x + 160 \\ 54x - 50x = 160 - 144 \\ 4x = 16 \\ x = \frac{16}{4} \\ x = 4$
Hence Man age is 6x 4 =24 years

Wife age is 5x 4 =20 years

so The husband age is 24 - 20 =4 years when wife is born.


$\huge{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{Hope \:it\: helps\: you}}}}}}}}}$