Question

Ratio of the present age of Paresh and Ramesh is 7 : 5 and the ratio of ages of Paresh before 3 years and Ramesh after 5 years is 1 : 1, then what is the average of their ages?
A) 24 years
B) 20 years
C) 22 years
D) 18 years

Answer 1

Answer:

D) 18 years

Step-by-step explanation:

Answer 2

✬ Average = 24 Years ✬

Step-by-step explanation:

Given:

• Ratio of present age of Paresh and Ramesh is 7 : 5.
• Ratio of ages of Paresh before 3 years and Ramesh after 5 years is 1 : 1.

To Find:

• What is average of their ages ?

Solution: Let x be the common in given ratios. Therefore,

➟ Paresh age = 7x years

➟ Ramesh age = 5x years

Now,

[ 3 years ago Paresh's age was ]

• (7x – 3) years

[ After 5 years Ramesh's age will be ]

• (5x + 5) years

A/q

• Ratio is of their age is 1 : 1.

$\implies{\rm }$ (7x – 3) : (5x + 5) = 1 : 1

$\implies{\rm }$ 7x – 3/5x + 5 = 1/1

$\implies{\rm }$ 1(7x – 3) = 1(5x + 5)

$\implies{\rm }$ 7x – 3 = 5x + 5

$\implies{\rm }$ 7x – 5x = 5 + 3

$\implies{\rm }$ 2x = 8

$\implies{\rm }$ x = 8/2

$\implies{\rm }$ x = 4

So, present age of

➙ Paresh = 7 × 4 = 28 Years

➙ Ramesh = 5 × 4 = 20 Years

★ Average = Sum of numbers/total numbers ★

• Average = 28 + 20/2
• 48/2
• 24

Hence average of their ages is 24 years.

(Option A is correct)