Math, asked by anwesha365, 2 months ago

Ratio of the volumes of a right circular cylinder and a sphere is 1:3.
Ratio of the radii of the cylinder and sphere is 1:3. If the sum of the
height and radius of the base of the cylinder is 78 cm, then what will
be the height of the cylinder?


Please give a correct answer. Unnecessary things will not be cooperated. Right answers will be marked 'Brainliest'​

Answers

Answered by adityakumar192004143
1

the answer will be 72 cm.

Attachments:
Answered by tennetiraj86
2

Step-by-step explanation:

Given:-

Ratio of the volumes of a right circular cylinder and a sphere is 1:3. Ratio of the radii of the cylinder and sphere is 1:3. If the sum of the height and radius of the base of the cylinder is 78 cm.

To find:-

what will be the height of the cylinder?

Solution:-

Given that

Ratio of the radii of the cylinder and sphere is 1:3.

Let the radius of the cylinder be X cm

r=X cm

Let the radius of the sphere = 3X cm

R=3X cm

Ratio of the volumes of a right circular cylinder and a sphere is 1:3.

We know that

Volume of a cylinder = πr^2h cubic units

Volume of a Sphere= (4/3)πR^3 cubic units

=>πr^2h : (4/3)πR^3 = 1:3

=>πr^2h / (4/3)πR^3 = 1/3

=>r^2h / (4/3)R^3 = 1/3

=>X^2 h / (4/3)(3X)^3 = 1/3

=>X^2 h / (4/3)(27X^3) = 1/3

Cancelling X^2 term

=>h / (4/3)27X = 1/3

=>h/4(9X) = 1/3

=>h/36X = 1/3

On applying cross multiplication then

=>3h = 36X

=>h = 36X/3

=>h = 12X cm-----------(1)

Now,

Given that

the sum of the height and radius of the base of the cylinder is 78 cm.

h+r = 78 cm

=>h+ X = 78 cm

On Substituting the value of h from (1) then

=> 12X+X = 78

=>13 X = 78

=>X = 78/13

=>X = 6 cm

Radius of the Cylinder =6 cm

On Substituting the value of the radius in (1) then

h = 12×6

h = 72 cm

Height of the Cylinder = 72 cm

Answer:-

The value of the height of the cylinder is 72 cm

Used formulae:-

  • Volume of a cylinder = πr^2h cubic units
  • Volume of a Sphere= (4/3)πR^3 cubic units
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