ratio of the wavenumber of the first line of lumen series of hydrogen atom to the first line of balmer series of he+ ion will be
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Answer:
ANSWER
Wavelength is given by
λ
1
=RZ
2
[
n
1
2
1
−
n
2
2
1
]
For first line of Lyman series, n
1
=1 and n
2
=2
λ
1
=RZ
2
[
1
2
1
−
2
2
1
]
λ
1
=RZ
2
×
4
3
λ∝
Z
2
1
λ
H
2
λ
Li
2+
=
Z
Li
2+
2
Z
H
2
2
=
3
2
1
=
9
1
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