Question

ratio of wavelength of the highest emission line of Balmer series in hydrogen atom to that of lowest emission line of Paschen series He+ ion is? ​

Answer 1

Answer:

1

=109678[

n

1

2

1

−

n

2

2

1

]

lost balmer line

λ

1

1

=109678[

2

2

1

−

∞

1

]

last laymen line

λ

1

=109678[1−

∞

1

]

λ

1

:λ

2

=4

Explanation:

mark me as brain list